-50=-4.905x^2

Solution for -50=-4.905x^2 equation:

-50=-4.905x^2

We move all terms to the left:

-50-(-4.905x^2)=0

We get rid of parentheses

4.905x^2-50=0

a = 4.905; b = 0; c = -50;
Δ = b2-4ac
Δ = 02-4·4.905·(-50)
Δ = 981
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{981}=\sqrt{9*109}=\sqrt{9}*\sqrt{109}=3\sqrt{109}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-3\sqrt{109}}{2*4.905}=\frac{0-3\sqrt{109}}{9.81}
=-\frac{3\sqrt{109}}{9.81}
=-\frac{\sqrt{109}}{3.27}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+3\sqrt{109}}{2*4.905}=\frac{0+3\sqrt{109}}{9.81}
=\frac{3\sqrt{109}}{9.81}
=\frac{\sqrt{109}}{3.27}
$